How do you find the horizontal asymptote for #y = x / (x-3)#?

1 Answer
Jul 11, 2018

Answer:

#"horizontal asymptote at "y=1#

Explanation:

#"Horizontal asymptotes occur as"#

#lim_(xto+-oo),yto c" (a constant)"#

#"divide terms on numerator/denominator by "x#

#y=(x/x)/(x/x-3/x)=1/(1-3/x)#

#"As "xto+-oo,yto1/(1-0)#

#y=1" is the asymptote"#
graph{x/(x-3) [-10, 10, -5, 5]}