From the given equation
#y=1/2*sin(x-pi)#
Compute the rectangular coordinate points #(x, y)#
#x# in degrees and radians
#"degrees x y " " " " y in decimals"#
#" "0##" "0##" "0##" "0#
#" "30##" "pi/6##" "-1/4##" "-0.25#
#" "45##" "pi/4##" "(-sqrt2)/4##" "-0.3535533906#
#" "60##" "pi/3##" "(-sqrt3)/4##" "-0.4330127019#
#" "90##" "pi/2##" "-1/2##" "-0.5#
#" "120##" "(2pi)/3##" "(-sqrt3)/4##" "-0.4330127019#
#" "135##" "(3pi)/4##" "(-sqrt2)/4##" "-0.3535533906#
#" "150##" "(5pi)/6##" "-1/4##" "-0.25#
#" "180##" "pi##" "0##" "0#
#" "210##" "(7pi)/6##" "1/4##" "0.25#
#" "225##" "(5pi)/4##" "(sqrt2)/4##" "0.3535533906#
#" "240##" "(4pi)/3##" "(sqrt3)/4##" "0.4330127019#
#" "270##" "(3pi)/2##" "1/2##" "0.5#
#" "300##" "(5pi)/3##" "(sqrt3)/4##" "0.4330127019#
#" "315##" "(7pi)/4##" "(sqrt2)/4##" "0.3535533906#
#" "330##" "(11pi)/6##" "1/4##" "0.25#
#" "360##" "2pi##" "0##" "0#
The draw your graph
graph{(y-1/2*sin(x-pi))=0[-5,5,-2.5,2.5]}
God bless....I hope the explanation is useful.