# How do you find the important points to graph y=f(x)=x^2+1?

${x}^{2} + 1$ tells us something important. On the parent graph of ${x}^{2}$, the important points are $x = 0$, $y = 0$. The $+ 1$ in this equation tells us that it's the same graph, except it has been shifted up one unit. So instead of $\left(0 , 0\right)$, now the x-intercept is $\left(0 , 1\right)$. All the normal points in ${x}^{2}$ have kept their $x$ values, but the $y$ values have increased by $1$.