# How do you find the indefinite integral of int 3^x?

${3}^{x} / \left(\ln 3\right)$
${3}^{x} = {e}^{x \ln 3}$ so $\int {3}^{x} \mathrm{dx} = \int {e}^{x \ln 3} \mathrm{dx} = {e}^{x \ln 3} / \left(\ln 3\right) = {3}^{x} / \left(\ln 3\right)$