Question

How do you find the indefinite integral of `((sqrt(x) + (3/x) - 4 e^x)) dx`?

Answer 1

`2/3sqrt(x^3)+3lnx-4e^x+C`

Explanation:

Rewriting in a different form using laws of exponents and surds, and then integrating term by term using normal rules of integration, we get :

`int(x^(1/2)+3*1/x-4e^x)dx`

`=(x^(3/2))/(3/2)+3lnx-4e^x+C`

`=2/3sqrt(x^3)+3lnx-4e^x+C`