Question

How do you find the instantaneous rate of change for `f(x) = x^2 + 3x + 4` for x=2?

Answer 1

Reqd. rate `=f'(2)=7.`

Explanation:

Reqd. rate `=f'(2)=[d/dx(x^2+3x+4)]_(x=2)`

=`[2x+3]_(x=2)=4+3=7.`