Question

How do you find the instantaneous rate of change for `f(x) = x^3 + 1` for x=1?

Answer 1

I found `3`.

Explanation:

The instantenous rate of change is equal to the derivative of your function evaluated at the particular `x` value:

`f'(x)=3x^2`

At `x=1`:

`f'(1)=3(1)^2=3`