Question

How do you find the instantaneous rate of change for `f(x)= x^3 +2x^2 + x` for [-1,2]?

Answer 1

Instantaneous rate of change :`f' (-1) = 0`

Explanation:

Start from the given `f(x) = x^3+ 2x^2+x` at `(-1, 2)`

`f' (x) = 3x^2+4x+1`

substitute `x=-1`

`f' (-1) = 3(-1)^2+4(-1)+1`

`f' (-1)= 0`