How do you find the instantaneous rate of change of the function #y=4x^3+2x-3# when x=2?
1 Answer
Jun 24, 2018
Explanation:
#"the instantaneous rate of change at a point is the"#
#"value of the derivative at that point, that is it is a"#
#"measure of the slope of the tangent line"#
#dy/dx=12x^2+2#
#x=2tody/dx=12(2)^2+2=50#
