How do you find the instantaneous rate of change of #y=5x+9# at x=2?

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Feb 17, 2017

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5

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#y = 5x + 9# is a line in the form of #y = mx + b#

This means that the slope #m# at any point will the the same value, in this case, #5#. (Lines have constants slopes or rates of change.)

Using derivatives, we find that the #y' = 5# which confirms that the slope is #5# regardless of what the #x# value is. We only need to find the slope at a specific #x# value if the derivative has an #x# term in it.

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