How do you find the integral of #cos(3x) dx#?

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Gió Share
Apr 14, 2016

Answer:

I found: #intcos(3x)dx=1/3sin(3x)+c#

Explanation:

Considering:
#intcos(3x)dx=#

we can set #3x=t#

so: #x=t/3#

and: #dx=1/3dt#

The integral becomes:

#int1/3cos(t)dt=1/3sin(t)+c#

going back to #x#:

we know that #t=3x#:

#=1/3sin(3x)+c#

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