Question

How do you find the integral of `e^((-1/2)*x)`?

Answer 1

`-2e^(-1/2x)+C`

Explanation:

`t=-1/2x => dt=-1/2dx => dx=-2dt`

`I=int e^(-1/2x)dx = int e^t*(-2dt) = -2 inte^tdt = -2e^t + C`

`I=-2e^(-1/2x)+C`