How do you find the integral of #int 5/sqrt(9-x^2)dx#?
We have that
Please see the explanation.
You can find the general form of the integral in any list of integrals:
However, I think you want to be shown how to do the trigonometric substitution that put this general form on the list. Let's begin:
Substitute the above into the integral:
Factor 9 from under the radical:
Use the identity
The numerator and denominator cancel to become 1:
To reverse the substitution, we need to describe