How do you find the integral of #sec^5 x dx#?

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Deb Share
Apr 11, 2018

Answer:

#1/6sec^6x#

Explanation:

first, to simplify, set #u=secx# (or not)

now we have #intu^5dx#

to integrate, bring the power 5 up to 6 and add #1/6# in front

so we have #1/6u^6#

so the answer is #1/6sec^6x#

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