Question

How do you find the integral of `sin^2 (5x)`?

Answer 1

`int (sin5x)^2*dx`

= `int 1/2*(1-cos10x)*dx`

= `1/2``int dx`-`1/2``int cos10x*dx`

=`x/2-1/20*sin10x+C`

Explanation:

1) I used `(sinax)^2=1/2*(1-cos2ax)` identity.

2) I used distribution rule of integral.

3) I found solution of it.