How do you find the integral of sin(x^2)?

1 Answer
May 22, 2018

color(blue)[intsin(x^2)*dx=(sqrtpi*S((sqrt2*x)/sqrtpi))/sqrt2+c]

Explanation:

show the steps below:

Substitute color(red)[u=(sqrt2*x)/sqrtpi

dx=sqrtpi/sqrt2*du

intsin(x^2)*dx

=sqrtpi/sqrt2intsin((pi*u^2)/2)*du

These is special integral Fresnel integral

=S(u)

Plug in solved integrals:

sqrtpi/sqrt2intsin((pi*u^2)/2)*du=(sqrtpi*S(u))/sqrt2

Undo substitution color(red)[u=(sqrt2*x)/sqrtpi

=(sqrtpi*S((sqrt2*x)/sqrtpi))/sqrt2+c