How do you find the intercepts for $2 x - 4 y = 12$ $2x-4y=12$ ?

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Answer 1 · 2015-07-06T23:12:33

You find the $y$ $y$ -intercept by setting $x = 0$ $x=0$ and vice versa.
But you may first divide everything by $2$ $2$

$\to x - 2 y = 6$ $->x-2y=6$

$y$ $y$ -intercept:
$0 - 4 y = 12 \to y = \frac{12}{- 4} = - 3 \to (0, - 3)$ $0-4y=12->y=12/-4=-3->(0,-3)$

$x$ $x$ -intercept:
$x - 2 \cdot 0 = 6 \to x = 6 \to (6, 0)$ $x-2*0=6->x=6->(6,0)$
graph{0.5*x-3 [-6.04, 13.96, -6.88, 3.12]}

How do you find the intercepts for 2x-4y=122x−4y=122x-4y=12?