How do you find the intercepts for #2x + y = 2#?

1 Answer
Jun 19, 2015

Answer:

Substitute #x=0# into the equation and solve to find the intercept #(0, 2)# with the #y# axis.

Substitute #y=0# into the equation and solve to find the intercept #(1, 0)# with the #x# axis.

Explanation:

The intercept with the #y# axis will be where #x=0#, so substitute #x=0# into the equation to get #y=2#. So the intercept with the #y# axis is at #(0, 2)#.

The intercept with the #x# axis will be where #y=0#, so substitute #y=0# into the equation to get #2x = 2#, hence #x=1#. So the intercept with the #x# axis is at #(1, 0)#.

graph{2x+y = 2 [-4.71, 5.29, -1.34, 3.66]}