# How do you find the intercepts for 3y=-6x+3?

x-intercept $= \frac{1}{2}$; y-intercept $= 1$
The x-intercept is the value of $x$ when $y = 0$
$\textcolor{w h i t e}{\text{XXXX}}$$3 \left(0\right) = - 6 x + 3 \Rightarrow x = \frac{1}{2}$
The y-intercept is the value of $y$ when $x = 0$
$\textcolor{w h i t e}{\text{XXXX}}$$3 y = - 6 \left(0\right) + 3 \Rightarrow y = 1$