How do you find the intercepts for #4x + 3y = 12#?

1 Answer
Jul 10, 2015

Answer:

x intercept #= 3#
y intercept #=4#

Explanation:

The x intercept is the value of #x# at the point where a graph of the equation crosses the x-axis. The x axis is the line along which #y=0#.
Therefore the x intercept is the value of #x# when #y# is set to #0# in the equation.
#color(white)("XXXX")##4x+3(0) = 12#
#color(white)("XXXX")##color(white)("XXXX")##rArr x = 3#

Similarly, the y intercept is the value of #y# at the point where a graph of the equation crosses the y-axis. The y axis is the line along which #x=0#.
Therefore the y intercept is the value of #y# when #x# is set to #0# in the equation.
#color(white)("XXXX")##4(0)+3y = 12#
#color(white)("XXXX")##color(white)("XXXX")##rArr y = 4#