How do you find the intercepts for #4x+3y=8#?

2 Answers
Mar 25, 2018

Answer:

#x#-intercept#(2,0)#
#y#-intercept#(0,8/3)#

Explanation:

To find the #x#-intercept, substitute #y=0#,

#4x=8#
#x=2#

To find the #y#-intercept, substitute #x=0#,

#3y=8#
#y=8/3#

Hence, the #x#-intercepts and #y#-intercepts are #(2,0)# and #(0,8/3)# respectively.

Mar 25, 2018

Answer:

The graph intersects the #X# axis in #P_1(2,0)# and the #Y# axis in #P_2(0,8/3)#.

Explanation:

The graph intersects the #Y# axis when #X=0# and the #X# axis when #Y=0#. Therefore, taking #4x+3y=8# and the cases:

  1. When #x=0#:
    #3y=8 => y=8/3#
    #P_2(0,8/3)#

  2. When #y=0#:
    #4x=8 => x=8/4=2#
    #P_1(2,0)#

graph{4x+3y=8 [-7.024, 7.02, -3.51, 3.51]}