# How do you find the intercepts for 5y=5x+15?

Jun 28, 2015

y-intercept $= 3$
x-intercept $= - 3$

#### Explanation:

The y-intercept of an equation is the value of $y$ where the equation's line crosses the y-axis; that is it is the value of $y$ when $x = 0$
Substituting $x = 0$ in $5 y = 5 x + 15$ gives
$\textcolor{w h i t e}{\text{XXXX}}$$5 y = 5 \left(0\right) + 15$
$\textcolor{w h i t e}{\text{XXXX}}$$y = 3$

Similarly, the x-intercept of an equation is the value of $x$ when $y = 0$
Substituting $y = 0$ in $5 y = 5 x + 15$ gives
$\textcolor{w h i t e}{\text{XXXX}}$$5 \left(0\right) = 5 x + 15$
$\textcolor{w h i t e}{\text{XXXX}}$$5 x = - 15$
$\textcolor{w h i t e}{\text{XXXX}}$$x = - 3$