# How do you find the intercepts for #x-3y+7=0?

Jun 19, 2015

To find the intercept with the $x$ axis, let $y = 0$ and solve to find $x = - 7$

To find the intercept with the $y$ axis, let $x = 0$ and solve to find $y = \frac{7}{3}$

#### Explanation:

This line will intercept the $x$ axis where $y = 0$, so substitute $y = 0$ into the equation to get:

$x + 7 = 0$

Subtract $7$ from both sides to get $x = - 7$.

So the intercept is at $\left(- 7 , 0\right)$

The line will intercept the $y$ axis where $x = 0$, so substitute $x = 0$ into the equation to get:

$- 3 y + 7 = 0$

Add $3 y$ to both sides to get:

$7 = 3 y$

Divide both sides by $3$ to get:

$y = \frac{7}{3}$

So the intercept is at $\left(0 , \frac{7}{3}\right)$