# How do you find the intercepts for y=-3x+3?

Jun 14, 2015

The intercept with the $y$ axis is where $x = 0$, hence $y = - 3 \cdot 0 + 3 = 3$. That is $\left(0 , 3\right)$

The intercept with the $x$ axis is where $y = 0$, hence $0 = - 3 x + 3$, hence $x = 1$. That is $\left(1 , 0\right)$

#### Explanation:

To find where $y = - 3 x + 3$ intercepts the $y$ axis, substitute $x = 0$ into the equation to find:

$y = \left(- 3 \cdot 0\right) + 3 = 0 + 3 = 3$.

That is $\left(0 , 3\right)$

To find where $y = - 3 x + 3$ intercepts the $x$ axis, substitute $y = 0$ into the equation to find:

$0 = - 3 x + 3$

Add #3x to both sides to get:

$3 x = 3$

Divide both sides by $3$ to get:

$x = 1$.

That is $\left(1 , 0\right)$

graph{-3x+3 [-9.5, 10.5, -3, 7]}