How do you find the intercepts of # 4y = 2x +6#?

1 Answer
Aug 10, 2016

Answer:

# x= -3 and y = 3/2#

Explanation:

A line has an x-intercept and a y-intercept, the points where it crosses the x-axis and the y-axis respectively.

On the y-axis, #x = 0 # and on the x-axis, #y = 0.#

In #4y = 2x +6#

To find the y-intercept , make #x=0#

#4y = 0 +6" "rArr y = 6/4 = 3/2#

To find the x-intercept , make #y=0#

#0 = 2x +6" " rArr 2x =-6 " " rArr x = -3#