How do you find the intercepts of # 4y = 2x +6#?

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Answer 1 · 2016-08-10T21:13:20

# x= -3 and y = 3/2#

A line has an x-intercept and a y-intercept, the points where it crosses the x-axis and the y-axis respectively.

On the y-axis, #x = 0 # and on the x-axis, #y = 0.#

In #4y = 2x +6#

To find the y-intercept , make #x=0#

#4y = 0 +6" "rArr y = 6/4 = 3/2#

To find the x-intercept , make #y=0#

#0 = 2x +6" " rArr 2x =-6 " " rArr x = -3#