How do you find the inverse of #(2x+7)/(3x-1)# and is it a function?

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Answer 1 · 2016-05-12T19:51:48

#f^-1(x)=(x+7)/(3x-2)#

#f(x)=y=(2x+7)/(3x-1)#

#3xy-y=2x+7#

#3xy-2x=y+7#

#x(3y-2)=y+7#

#x=(y+7)/(3y-2)#

#"change x and y vice versa"#

#f^-1(x)=(x+7)/(3x-2)#

#"There isn't any value which it does undefined the denominator"#

#"it is a function"#