Question

How do you find the inverse of `f(x) = (2x)/(x-1)`?

Answer 1

We have that

`y=(2x)/(x-1)=>y*(x-1)=2x=>yx-y=2x=>(y-2)*x=y=>x=y/(y-2)`

hence the inverse is

`f^(-1)(x)=x/(x-2)`