How do you find the inverse of f(x)=3^(x-1)-2f(x)=3x−1−2?

1 Answer
Sid P.
Dec 29, 2015

x=2.096log(f(x)+2)+1x=2.096log(f(x)+2)+1

Explanation:

f(x)=3^(x-1)-2f(x)=3x−1−2
f(x)+2=3^(x-1)f(x)+2=3x−1
taking log both sides
log(f(x)+2)=log3^(x-1)log(f(x)+2)=log3x−1
log(f(x)+2)=(x-1)*log3log(f(x)+2)=(x−1)⋅log3
x-1=log(f(x)+2)/log(3)x−1=log(f(x)+2)log(3)
x=2.096log(f(x)+2)+1x=2.096log(f(x)+2)+1

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