How do you find the inverse of $f(x) = 3log(x-1)$ ?

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Answer 1 · 2015-11-29T14:46:44

$y=log^(-1)(x/3)+1$

Write as $y=3log(x-1)$

Manipulate to give:

$log(x-1)=y/3$

$log^(-1)(x-1)=log^(-1)(y/3)$

$x-1=log^(-1)(y/3)$

$x=log^(-1)(y/3)+1$

Now swap the $x$ and $y$ giving:

$y=log^(-1)(x/3)+1$

How do you find the inverse of f(x) = 3log(x-1) f(x) = 3log(x-1)?