How do you find the inverse of # f(x) = 3log(x-1)#?

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Answer 1 · 2015-11-29T14:46:44

#y=log^(-1)(x/3)+1#

Write as #y=3log(x-1)#

Manipulate to give:

#log(x-1)=y/3#

#log^(-1)(x-1)=log^(-1)(y/3)#

#x-1=log^(-1)(y/3)#

#x=log^(-1)(y/3)+1#

Now swap the #x# and #y# giving:

#y=log^(-1)(x/3)+1#