How do you find the inverse of #f(x)=3sqrt(x+2)#?

1 Answer
Dec 5, 2015

#x=y^2/9-2#

Explanation:

Since #f(x)=y#, you need to isolate #x# and express it in terms of #y#, while now you have written #y# in terms of #x#. So, here are the steps:

#y=3sqrt(x+2)#

#y/3 = sqrt(x+2)# (divided both members by #3#)

#y^2/9 = x+2# (squared both members)

#y^2/9-2 = x# (subtracted #2# from both terms)

And here we go!