How do you find the inverse of $f(x) = 3x + 1$ and is it a function?

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Answer 1 · 2016-03-22T00:13:47

See explanation...

Let $y = f(x) = 3x+1$

Subtract $1$ from both ends to get:

$y - 1 = 3x$

Divide both sides by $3$ and transpose to get:

$x = (y-1)/3$

Having expressed $x$ in terms of $y$ , we can deduce that:

$f^(-1)(y) = (y-1)/3$

Since $f^(-1)(y)$ is uniquely defined for any $y in RR$ , it is a function.

How do you find the inverse of f(x) = 3x + 1f(x) = 3x + 1 and is it a function?