How do you find the inverse of #f(x) = 4(x + 5)^2 - 6#?

1 Answer
Nov 16, 2015

No inverse function exists.

Explanation:

If there is no boundary on the domain, #f(x)# has no inverse function .

It would have been possible, however, if the was a boundary like #x >= -5#.

Why is this? Let me show you how to compute the inverse if there was one.

First, set #y = f(x)#:
#y = 4(x+5)^2 - 6#

Next, exchange the roles of #x# and #y#:
#x = 4(y+5)^2 - 6#

Now, try to solve this equation for #y# in terms of #x#:

... add #6# on both sides ...
# x + 6 = 4(y+5)^2#

... divide by #5# on both sides...
# (x+6)/4 = (y+5)^2#

Unfortunately there is no unique way to invert the square function since both the positive and the negative roots are solutions
(E.g. #x^2 = 9# has two solutions: #x = 3# and #x = -3# since both #3^2 = 9# and #(-3)^2 = 9# hold.)

This means that we would get something like:
# +- sqrt((x+6)/4) = y+5#

And finally, adding #-5# on both sides gives us:
#y = -5 +- sqrt ((x+6)/4)#

However, this means that for a unique value of #x# you don't get a unique value of #y# but two different values. This means that this is no function and thus, your problem has no solution.