How do you find the inverse of f(x)=ex1?

1 Answer
Jan 23, 2016

f1(x)=loge(x+1)

Explanation:

Firstly, I'll assume you know that if f(x)=y then f1(y)=x

So now, f(x)=ex1
Rearranging the equation, and taking y=f(x) we get y+1=ex
Applying log of base e on both sides loge(y+1)=x
Now, given above that f1(y)=x
So this means, f1(y)=loge(y+1)

Replacing y as x you'll get the answer.