How do you find the inverse of #f(x)=(e^x)/x#?

1 Answer
Nov 30, 2015

Using the Lambert W function, we find that #f^-1(x) = -W(-1/x)#

Explanation:

A typical way of finding the inverse of a function #f(x)# is to set #y = f(x)# and then solve for #x#. The result will be #x = f^(-1)(y)#

(This method should make sense intuitively, as plugging in #f(x)# for #y# gives you the definition of the inverse function).

Trying that here, however, will lead to some frustration, as no basic function will be enough to solve for #x#. Instead, what is needed is a function called the Lambert W function. The Lambert W function works like so:
#W(xe^x) = x#

With this special function as a tool, we can now find the inverse.

Set #y = f(x) = e^x/x#

#=> xy = e^x#

#=> x/e^x = 1/y#

#=> xe^(-x) = 1/y#

#=> (-x)e^(-x) = -1/y#

#=> W((-x)e^(-x)) = W(-1/y)#

#=> -x = W(-1/y)#

#=>x = -W(-1/y)#

Thus we have #f^-1(y) = -W(-1/y)#

So our inverse function is

#f^-1(x) = -W(-1/x)#