How do you find the inverse of #f(x) = -log2^x#?

1 Answer
Jun 20, 2016

#f^-1(x)=log_2(10^{-x})#

Explanation:

To find the inverse of a function, there are always a few standard steps to be taken.

Step 1) Swap the function and the variable on the other side of the equation.

#f(x)=-log(2^x) rArr x=-log(2^{f^-1(x)})#

Step 2) Isolate the now swapped inverse function.

#-log(2^{f^-1(x)})=x#

#log(2^{f^-1(x)})=color(red)(-)x#

#2^{f^-1(x)}=color(red)(10)^-x#

#f^-1(x)=color(red)(log_2)(10^-x)#

Giving you the inverse function.

If the function is truly inverse, the original function will have been reflected along #y=x# (Which it has):
graph{(y+log(2^x))(y-log(0.1^x)/log(2))=0 [-10, 10, -5, 5]}