Question

How do you find the inverse of `f(x)=sqrt(2x+5)`?

Answer 1

`f'(x)=(x^2-5)/2`

Explanation:

`y=sqrt(2x+5)`

First, we switch the `x`s and `y`s to get `x=sqrt(2y+5)`

Now, we must rearrange to make `y` the subject:
`x^2=(sqrt(2y+5))^2=2y+5`
`x^2-5=2y`
`y=(x^2-5)/2`