How do you find the inverse of $f(x)=x^2$ and graph both f and $f^-1$ ?

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Answer 1 · 2017-02-21T15:56:32

$f^-1 = sqrt x$

Let $f(x)=y=x^2$ . For finding $f^-1$ , interchange x and y and solve for y. Thus,

$x= y^2 -> y = sqrtx$

$f^-1$ is thus $sqrt x$

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How do you find the inverse of f(x)=x^2f(x)=x^2 and graph both f and f^-1f^-1?