How do you find the inverse of #f(x)= x/(x-9)#?

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Answer 1 · 2016-04-14T16:15:36

#f^-1(x)=(9x)/(x-1)#

#f(x)=x/(x-9)#

#y=x/(x-9)#

#y x-9y=x#

#y x-x=9y#

#x(y-1)=9y#

#x=(9y)/(y-1)#

#"now change x and y vice versa"#

#y=(9x)/(x-1)#

#f^-1(x)=(9x)/(x-1)#