How do you find the inverse of #g(x)= log_8(4 x+6)#?

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Answer 1 · 2018-07-05T14:43:01

I tried this:

I would first use the definition of log to write:

#4x+6=8^g(x)#

isolate #x#:

#4x=8^g(x)-6#

#x=(8^g(x)-6)/4#

so we can rewrite it as the inverse #f#:

#f(x)=(8^x-6)/4#

hope it helps!