How do you find the inverse of $h (x) = - 3 x + 6$ $h(x)=-3x+6$ and is it a function?

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Answer 1 · 2016-06-28T09:03:29

The inverse function is $h^{- 1} (x) = - \frac{1}{3} x + 2$ $h^(-1)(x)=-1/3x+2$

To find the inverse function starting from $y = - 3 x + 6$ $y=-3x+6$ you have to calculate $x$ $x$ in terms of $y$ $y$

$y = - 3 x + 6$ $y=-3x+6$

$3 x = - y + 6$ $3x=-y+6$

$x = - \frac{1}{3} y + 2$ $x=-1/3y+2$

Now we can write the inverse function returning to standard names of variables:

$h^{- 1} (x) = - \frac{1}{3} x + 2$ $h^(-1)(x)=-1/3x+2$

To find out if it is a function we have to find out if it fulfills 2 conditions:

$h^{- 1}$ $h^(-1)$ is a linear expression so it fulfills both conditions. This means it is a function.

How do you find the inverse of h(x)=−3x+6h(x)=-3x+6 and is it a function?