Question

How do you find the inverse of `H(x)=log x`?

Answer 1

We have that

`y=log_10 x=>10^y=x` hence the inverse is

`H^(-1) (x)=10^x`

(Assuming that the base of the logarithm is 10)

If the base of the logarithm is b then

`H^(-1)(x)=b^x`