Question

How do you find the inverse of `h(x)= x^2 - 4x + 5` and is it a function?

Answer 1

Inversion gives two forms for `x = 2+-sqrt(h-1), h>=1`

Explanation:

The for this equation is a parabola

`(x-2)^2=y-1>=0, and` so, `y>=1`,

The parabola is symmetrical about its axis x = 2.

Explicitly, the inverse functions are

`x = 2+-sqrt(h-1), h>=1`, representing the halves of the parabola,

bifurcated by x = 2.l