How do you find the inverse of $log _ 1.25 (x)=y$ ?

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Answer 1 · 2018-06-05T08:37:57

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By definition of logarithm $log_1.25x=y hArr y^(1.25)=x$

But we know that $1.25=5/4$

$y^(5/4)=x$ powering both sides to 4 we have

$(y^(5/cancel4))^cancel4=x^4$

$y^5=x^4$ stracting 5th root

$root(5)(y^5)=y=root(5)(x^4)=x^(4/5)$

How do you find the inverse of log _ 1.25 (x)=ylog _ 1.25 (x)=y?