Question

How do you find the inverse of `log 2^-x`?

Answer 1

Step by Step process is given below.

Explanation:

`y=log(2^(-x))`

Note (x,y) inverse is (y,x) to get the inverse function we need to do the following steps.

`1.` swap `x` and `y`
`x=log(2^(-y))`

`2.` solve for `y`

`x=-y*log(2)` using `log(a^n) = nlog(a)`
`-x=log(2)y`
`-x/log(2) =y`

The inverse function is `f^-1(x) = -x/log(2)`