How do you find the inverse of #y = 13/x # and is it a function?

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Answer 1 · 2017-02-24T17:12:20

The inverse is itself and yes, it is a function from #CC - {0}# to #CC#.

#f(x) = y Rightarrow x = f^(-1)(y)#

Given y, how do you find x?

Multiply by #x#.

#xy = 13#

Divide by #y#.

#x = 13/y = f^(-1)(y)#

#13/text{thing} = f^(-1)(text{thing})#

#13/x = f^(-1)(x) = f(x)#