Question

How do you find the inverse of `y = 2^(3 - x)` and is it a function?

Answer 1

The inverse function is `3-x= log_2y`, and so, `x= 3-log_2 y=3-log y/log 2`

Explanation:

Use the inversion formula X = log_-b y`,, if y=b^X` and

`log_b a = log_c a/log_c b`, with c at your choice.

Here, the inverse is `3-x=log_2 y=log y/log 2`.

So, `x = 3- log y/log 2`.-, .