Question

How do you find the inverse of `y=3x^2-2` and is it a function?

Answer 1

`y^-1=±sqrt((x+2)/3)`

Explanation:

`y=3x^2-2`
`y+2=3x^2`
`x^2=(y+2)/3`
`x=±sqrt((y+2)/3)`
`"change x as y and y as x"`
`y^-1=±sqrt((x+2)/3)`