How do you find the inverse of #y = 3x-9# and is it a function?

1 Answer
Apr 25, 2016

#x=(y+8)/3#. In general, if y=f(x), a function of x, #f^(-1)(y)=x#.
The operators# f and f^(-1)# are each the inverse operator for the other.

Explanation:

Solving for x, #x=(y+8)/3#.
In inversions, y may be a single-valued function of x. But, inversely, x might be many-valued, and vice versa.

For example, #y =x^2 > 0#, is single, valued. Inversely, #x=+-sqrt y# has two values.

In the example, #y=sin^(-1)x# is many-valued. The inverse x = sin y is single-valued.