How do you find the inverse of #y=6^(x)+1#?

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Answer 1 · 2016-01-02T17:36:59

#y=log_6(x-1)#

Flip the #x# and #y# and solve for #y#.

#x=6^y+1#

#x-1=6^y#

To undo the exponentiation, take the logarithm with base #6# of both sides.

#log_6(x-1)=log_6(6^y)#

The logarithm will undo the exponent.

#log_6(x-1)=y#