How do you find the inverse of y=log_(1/2) xy=log12x?
2 Answers
Jan 9, 2016
It's
by logic you put
You find the identity application so
Jan 9, 2016
Explanation:
Given
By the nature of what a log is, another way of writing the given relationship is:
As it turns out this is exactly the format needed for the inverse function. All you have to now do is swap the variable letters round to give:
So if
Then
Or, if you prefer